Published by:
CGP EDU Academic Team
Published on: August 14, 2026
1 g of complex [Cr(H 2 O) 5 Cl]Cl 2 .H 2 O was passed through a cation exchanger to produce HCl. The acid liberated was diluted to 1 litre. What will be the molarity of acid solution [Molecular weight of complex = 266.5] ?
Text Solution
Verified by ExpertsThe correct answer is:
0.0075.
(0.0075.)
Sol. 1 mole of complex will give two moles of Cl – ion, i.e. 2 mole HCl
[Cr(H 2 O) 5 Cl]Cl 2 . H 2 O 
[Cr(H 2 O) 5 Cl] +2 + 2Cl –
1 g
mole of HCl = 
(for HCl, V.f. = 1 ∴ N = M)
∴ N = 
= 0.0075.
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